Step 1: Reflect each vertex across the y-axis using the rule
\((x, y) → (−x, y)\)
\begin{align*}
\amp A(−6, 1) → A′(6, 1)\\
\amp B(−2, 1) → B′(2, 1)\\
\amp C(−4, 5) → C′(4, 5)
\end{align*}
Step 2: Calculate side lengths of the original flower bed:
\begin{align*}
AB = \amp |(−2) − (−6)| = 4 \,\text{units}\\
AC = \amp \sqrt{−4−(−6)}² + (5−1)²) = \sqrt{4 + 16} = \sqrt{20} = 2\sqrt{5} \,\text{units}\\
BC = \amp \sqrt{−4−(−2)}² + (5−1)²) = \sqrt{4 + 16} = \sqrt{20} = 2\sqrt{5} \,\text{units}
\end{align*}
Step 3: Calculate side lengths of the reflected flower bed:
\begin{align*}
A′B′ = \amp|(2) − (6)| = 4\; \text{units}\\
A′C′ = \amp \sqrt{(4−6)² + (5−1)²} = \sqrt{4 + 16} = \sqrt{20} = 2\sqrt{5} \,\text{units}\\
B′C′ = \amp \sqrt{(4−2)² + (5−1)²} = \sqrt{4 + 16} = \sqrt{20} = 2\sqrt{5} \,\text{units}
\end{align*}
Step 4:
\(AB = A′B′ = 4, AC = A′C′ = 2\sqrt{5}, BC = B′C′ = 2\sqrt{5}\)
Therefore,
\(△ABC ≅ △A′B′C′\) by the SSS criterion. The two flower beds are congruent.