Step 1: Reflect each vertex across the y-axis using the rule
\((x, y) β (βx, y)\)
\begin{align*}
\amp A(β6, 1) β Aβ²(6, 1)\\
\amp B(β2, 1) β Bβ²(2, 1)\\
\amp C(β4, 5) β Cβ²(4, 5)
\end{align*}
Step 2: Calculate side lengths of the original flower bed:
\begin{align*}
AB = \amp |(β2) β (β6)| = 4 \,\text{units}\\
AC = \amp \sqrt{β4β(β6)}Β² + (5β1)Β²) = \sqrt{4 + 16} = \sqrt{20} = 2\sqrt{5} \,\text{units}\\
BC = \amp \sqrt{β4β(β2)}Β² + (5β1)Β²) = \sqrt{4 + 16} = \sqrt{20} = 2\sqrt{5} \,\text{units}
\end{align*}
Step 3: Calculate side lengths of the reflected flower bed:
\begin{align*}
Aβ²Bβ² = \amp|(2) β (6)| = 4\; \text{units}\\
Aβ²Cβ² = \amp \sqrt{(4β6)Β² + (5β1)Β²} = \sqrt{4 + 16} = \sqrt{20} = 2\sqrt{5} \,\text{units}\\
Bβ²Cβ² = \amp \sqrt{(4β2)Β² + (5β1)Β²} = \sqrt{4 + 16} = \sqrt{20} = 2\sqrt{5} \,\text{units}
\end{align*}
Step 4:
\(AB = Aβ²Bβ² = 4, AC = Aβ²Cβ² = 2\sqrt{5}, BC = Bβ²Cβ² = 2\sqrt{5}\)
Therefore,
\(β³ABC β
β³Aβ²Bβ²Cβ²\) by the SSS criterion. The two flower beds are congruent.