Subsection2.2.1Identifying the Gradient in Real-Life Situations
In our everyday environment we notice many surfaces that are slanted rather than perfectly flat. Think of the gentle incline of a ramp at your school, or the varying steepness of a hill on a familiar route. These everyday features are examples of what we call a \(\textbf{gradient}\text{.}\)
Instead of focusing on the mathematics immediately, it is important to understand that the gradient describes how steep a path is. It tells us how quickly something rises or falls over a certain distance.
Observe and discuss with your group what βsteepnessβ might mean in a real-life context. Is a gently inclined ramp different from a steep staircase?
Discuss as a group how the steepness might affect the use of that surface (for example, ease of access for a wheelchair or the energy required for a person climbing the hill).
Discuss as a group how the steepness might affect the use of that surface (for example, ease of access for a wheelchair or the energy required for a person climbing the hill).
The gradient gives a numerical value to the concept of steepness, allowing us to compare different slopes and understand their practical implications for safety, accessibility, and design.
Subsection2.2.2Determining the Gradient from Two Known Points
In many situations, we are given two points on a straight path and want to determine how steep that path is. These two points may represent physical locations, price changes, distances over time, or any relationship that forms a straight line.
To calculate the gradient between any two points on a straight line, we compare how much the value changes vertically (rise) with how much it changes horizontally (run).
The gradient between two points shows how steep the line is. It is found by dividing the change in \(y\) values (rise) by the change in \(x\) values (run).
Subsection2.2.3Determining the Equation of a Line Given Two Points
Once you have learned how to calculate the gradient between two points, the next step is to use those two points to determine the unique equation of the line that connects them.
In this section, we will introduce the idea that every straight line in the coordinate plane can be defined by its \(\textbf{gradient}\) and a point it passes through. This leads us to the \(\textbf{point-slope form}\) of a line, which can later be rearranged into the slope-intercept form:
By determining the gradient between two points and substituting one of the points into the point-slope equation, we can derive the unique linear equation that passes through both points. This equation can then be rearranged into the form \(y = mx + c\text{.}\)
Subsection2.2.4Determining the Equation of a Line from a Known Gradient and a Point
In some cases, we may be told the \(\textbf{gradient (m)}\) of a line and given only one point that lies on it. Using this information, we can still find the full equation of the line.
where \((x_1, y_1)\) is the known point and \(m\) is the gradient. We can rearrange this into the familiar slope-intercept form: \(y = mx + c \text{.}\)
When given a gradient and one point on a line, you can use the point-slope form to find the full equation of the line. This method is efficient and avoids the need for a second point.
A plumber charges a fixed fee of Ksh \(300\) and an additional Ksh \(150\) per hour worked. Let \(x\) represent the number of hours worked and \(y\) represent the total charge. Write the equation connecting \(x\) and \(y\text{.}\)
Subsection2.2.5Determining the x and y-intercepts of a Line
When sketching or interpreting a linear graph, it is helpful to know where the line crosses the axes. These points are called the \(\textbf{intercepts}\text{.}\)
The y-intercept is found by setting \(x = 0\text{.}\) The x-intercept is found by setting \(y = 0\text{.}\) These two points are enough to sketch a linear graph accurately.
A mobile data company charges a base fee of Ksh \(100\) and Ksh \(20\) per GB. Write the cost equation, and find how many GB one can get when the total cost is Ksh \(300\text{.}\)
Subsection2.2.6The Use of Equations of Straight Lines in Real Life
Linear equations are not just for the classroom, they appear all around us in daily life. Any situation that involves a fixed starting value and a constant rate of change can be modelled using a straight-line equation of the form \(y = mx + c\text{.}\)
Everyday life situations involving steady increase or decrease can be modelled using linear equations. This makes it easier to predict, budget, or compare.
A mobile provider charges Ksh \(50\) per GB of data and a flat connection fee of Ksh \(100\text{.}\) Write the equation that models the total cost \(y\) in terms of data used \(x\text{.}\)
A vehicle travels at a constant speed. It covers 120 km in 2 hours and 180 km in 3 hours. Find the equation connecting time \(x\) (hours) to distance \(y\) (km).
A student earns Ksh \(200\) per week as allowance and Ksh \(50\) for every day they help in a shop. Write an equation to model the total amount earned in a week if they work for \(x\) days.
Reflect: Think of one more situation from your life or community that can be modelled using a straight-line equation. Describe it and write its equation.